5cos^2x+3sin^2x=4

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Solution for 5cos^2x+3sin^2x=4 equation: 


Simplifying
5cos2x + 3sin2x = 4

Solving
5cos2x + 3in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2sx' to each side of the equation.
5cos2x + 3in2sx + -3in2sx = 4 + -3in2sx

Combine like terms: 3in2sx + -3in2sx = 0
5cos2x + 0 = 4 + -3in2sx
5cos2x = 4 + -3in2sx

Divide each side by '5os2x'.
c = 0.8o-1s-2x-1 + -0.6in2o-1s-1

Simplifying
c = 0.8o-1s-2x-1 + -0.6in2o-1s-1

Reorder the terms:
c = -0.6in2o-1s-1 + 0.8o-1s-2x-1

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